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CorollaryStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-27
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The Bell numbers satisfy Bn+1=k=0n(nk)Bk

Statement

For every nN,

Bn+1=k=0n(nk)Bk.

Facts & Assumptions

Given: A partition of [n+1], counted by The Stirling numbers of the second kind and the Bell numbers.

Proof

technique · direct
1.1

Let S be the block containing n+1, and let T:=[n](S{n+1}). Then T is exactly the set of elements not lying in the distinguished block. If T=k, there are (nk) choices for T, and after that the elements of T may be partitioned arbitrarily in Bk ways.

given
1.2

Conversely, every choice of a subset T[n] and a partition of T determines a unique partition of [n+1]: put all elements of [n]T together with n+1 into one block and keep the chosen partition of T for the other blocks.

givenconstruct
2.1

Summing over all possible values k=T gives the claimed recurrence for Bn+1.

step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

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Sources