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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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Best affine prediction from one random variable

Statement

Let X and Y be square-integrable real random variables.

  • If Var(Y)>0, the unique best affine predictor of X from Y is E[X]+Cov(X,Y)Var(Y)(YE[Y]).
  • If Var(Y)=0, then every best affine predictor is almost surely equal to the constant E[X].

Facts & Assumptions

Given: Square-integrable real random variables X,Y.

[L1]

Best affine L2 predictors are characterized by the normal equations (Normal equations for best affine L2 prediction).

[L2]

Proof

technique · direct
1.1

With one predictor variable, the normal equation from [L1] is Cov(Y,Y)a1=Cov(X,Y). By [L2], this is Var(Y)a1=Cov(X,Y).

L1L2
2.1

If Var(Y)=0, then step 1.1 makes the normal equation 0a1=Cov(X,Y). Hence every real a1 solves it, and [L1] says that all corresponding affine predictors yield the same optimal class. Taking a1=0 gives the constant predictor E[X], so every best affine predictor is almost surely equal to that constant.

step 1.1L1L2algebra
2.2

If Var(Y)>0, step 1.1 gives a1=Cov(X,Y)Var(Y). Substituting this into the intercept formula from [L1] yields the displayed predictor a0+a1Y=E[X]+Cov(X,Y)Var(Y)(YE[Y]).

step 1.1L1L2algebra
3.1

Steps 2.2 and 2.1 give the positive-variance and zero-variance cases.

step 2.2step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources