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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Best polynomial errors vanish for continuous functions

Statement

For every f∈C[−1,1], En(f)→0 as n→∞. This statement concerns best polynomial errors only; it does not assert convergence of interpolation at arbitrary node arrays.

Facts & Assumptions

Given: f∈C[−1,1] and ε>0.

[F1]

Polynomials are uniformly dense in C([a,b],R) for every closed interval: every continuous real function on a closed interval is uniformly approximable by polynomials.

[F2]

Best uniform polynomial error and Chebyshev interpolation operators: En(f)=inf⁡p∈Pn∥f−p∥∞, and Pm⊆Pn when m≤n.

Proof

1.1givenF1choose

By [F1], choose a polynomial p and an integer m with p∈Pm such that ∥f−p∥∞<ε; if p=0, take m=0.

2.1givenF1F2step 1.1algebra∎

For every n≥m, p∈Pn, so [F2] gives 0≤En(f)≤∥f−p∥∞<ε. Since ε>0 was arbitrary, En(f)→0. This conclusion concerns En alone; it does not show that (1+Λnσ)En(f)→0.

Depends on

Used by

Dependency tree · two levels

19 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources