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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
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The BGG resolution has length the number of positive roots

Statement

Assume the Axiom of Choice (The Axiom of Choice). Let λ∈Λ+ and let w0∈W be the longest element. Then ℓ(w0)=∣Φ+∣ and ∣{w∈W:ℓ(w)=∣Φ+∣}∣=1, the BGG complex C∙(λ) is concentrated in degrees 0≤k≤∣Φ+∣, the top term is C∣Φ+∣(λ)=M(w0∘λ)≠0, and all higher terms vanish. Consequently the resolution has length ∣Φ+∣ and the last nonzero degree of the complex is ∣Φ+∣; in particular the alternating sum of The Euler-character identity for a finite-dimensional simple module is finite and has ∣W∣ terms.

Facts & Assumptions

Given: The Axiom of Choice, a dominant integral weight λ∈Λ+, the longest element w0∈W, and the BGG complex C∙(λ).

[F1]

w0Φ+=Φ−, w0 is the unique longest element, and ℓ(w)=∣Inv⁡(w)∣ for every w, where Inv⁡(w)={α∈Φ+:wα∈Φ−}; hence ℓ(w0)=∣Φ+∣ and ℓ(w)≤∣Φ+∣ for every w, with equality only for w=w0 (Finite Weyl closed chambers and stabilizers, Finite Weyl strong exchange and deletion, Finite Weyl positive roots and simple reflections).

[F2]

Ck(λ)=⨁ℓ(w)=kM(w∘λ) for 0≤k≤∣Φ+∣ and Ck(λ)=0 for k>∣Φ+∣; the summands are indexed by the elements of W of length k, and C∣Φ+∣(λ)=M(w0∘λ) because w0 is the unique element of maximal length (The Bruhat graph and the BGG Verma sum in degree k, Verma modules).

[F3]

M(ψ)≠0 for every weight ψ: M(ψ) has a nonzero highest weight vector vψ and u↦uvψ is a vector-space isomorphism U(n−)→∼M(ψ) (Verma modules, The PBW model of a Verma module).

[F4]

0→C∣Φ+∣(λ)→⋯→C1(λ)→C0(λ)→L(λ)→0 is exact; equivalently the unaugmented complex C∙(λ) has homology L(λ) in degree 0 and no homology in positive degrees (The BGG resolution of a finite-dimensional simple module).

[F5]

The Euler-character identity expresses [L(λ)] as the finite alternating sum ∑w∈W(−1)ℓ(w)[M(w∘λ)], whose terms are indexed by the elements of W (The Euler-character identity for a finite-dimensional simple module).

Proof

1.1F1

Since w0Φ+=Φ−, one has Inv⁡(w0)={α∈Φ+:w0α∈Φ−}=Φ+, so ℓ(w0)=∣Inv⁡(w0)∣=∣Φ+∣ by [F1]. If ℓ(w)=∣Φ+∣ for some w, then Inv⁡(w) is a subset of Φ+ of full cardinality, hence equals Φ+, so w sends every positive root to a negative root, wΦ+=Φ−, and by uniqueness of w0 in [F1] we get w=w0. Therefore ∣{w∈W:ℓ(w)=∣Φ+∣}∣=1 and ℓ(w0)=∣Φ+∣ and ∣{w∈W:ℓ(w)=∣Φ+∣}∣=1.

1.2F2F3

By [F2] the complex is concentrated in degrees 0,…,∣Φ+∣ with Ck(λ)=0 for k>∣Φ+∣, and the top term is C∣Φ+∣(λ)=M(w0∘λ); this is nonzero by [F3]. Hence the last nonzero degree of the complex is ∣Φ+∣ and the resolution of [F4] has length ∣Φ+∣.

1.3F5

The alternating sum of [F5] is ∑w∈W(−1)ℓ(w)[M(w∘λ)]: it is finite, and its terms are indexed by the ∣W∣ elements of the Weyl group, so it has exactly ∣W∣ terms.

2.1F4step 1.1step 1.2step 1.3∎

Combining: ℓ(w0)=∣Φ+∣ and ∣{w:ℓ(w)=∣Φ+∣}∣=1 by step 1.1; the complex is concentrated in degrees 0≤k≤∣Φ+∣ with top term M(w0∘λ)≠0 and all higher terms zero by step 1.2; the resolution has length ∣Φ+∣, its highest nonzero degree is ∣Φ+∣ (homology is concentrated in degree 0 by [F4]), and the alternating sum has ∣W∣ terms by step 1.3.

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