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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Connected Lie subgroups with the same Lie algebra are equal as immersed subgroups

Statement

Assume ACω. Two connected immersed Lie subgroups of a Lie group G with the same tangent Lie subalgebra have the same image and the same intrinsic immersed-subgroup structure: there is a unique Lie-group isomorphism between them commuting with their inclusions into G.

Facts & Assumptions

Given: ACω and connected immersed Lie subgroups i1:H1G and i2:H2G with the same tangent image hLie(G).

[F1]

A Lie subalgebra integrates to a connected immersed subgroup uniquely up to the unique isomorphism over G. Lie subgroup–Lie subalgebra correspondence.

Proof

technique · direct
1.1

Apply [F1] to the common subalgebra h. Its uniqueness clause supplies a Lie-group isomorphism ϕ:H1H2 satisfying i2ϕ=i1.

F1given
2.1

The equality i2ϕ=i1 gives i1(H1)=i2(H2) as subsets of G. Because ϕ and ϕ1 are smooth, they identify the intrinsic manifold structures, not merely the underlying image. The zero-dimensional and full-dimensional cases are included, and the stated countable-choice assumption is exactly the one inherited from [F1].

F1step 1.1algebra

Depends on

Used by

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Dependency tree · two levels

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Sources