Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-09-23 (gpt-6-sol)
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Unequal-depth equalities in a short exact sequence

Statement

Assume the Axiom of Choice (The Axiom of Choice). In the setting of thm-depth-lemma, the following implications hold: a<c⇒b=a,a>c+1⇒b=c,a<b⇒c=a−1,a>b⇒c=b,b<c⇒a=b,b>c⇒a=c+1. Only implications whose strict inequality is meaningful for the depth conventions are asserted.

Facts & Assumptions

Given: The Axiom of Choice; write a,b,c for the depths of A,B,C in the short exact sequence.

Proof

technique · direct
1.1given

The first Depth Lemma inequality and either of the other two give a<c⇒b=a and a>c+1⇒b=c. Cyclically applying the same comparison to the remaining inequalities gives the other four displayed implications.

2.1step 1.1algebra∎

For example, if a<c, then b≥a while a≥min⁡{b,c+1} forces a≥b; hence b=a. If a>c+1, then c≥min⁡{a−1,b} and a−1>c force c≥b, while b≥c; hence b=c. If a<b, then c≥a−1, while a≥min⁡{b,c+1} forces a≥c+1; hence c=a−1. The other three cases are the same comparisons.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources