Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-12
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Infinitely many pairwise distinguishable prefixes force nonregularity

Statement

Let LΣ. If there are infinitely many words in Σ that are pairwise distinguished by suffixes, then L is not regular.

Facts & Assumptions

Given: A language LΣ with infinitely many pairwise distinguishable words.

[L1]

By Distinguishing words for states and for prefixes, a suffix distinguishes two words exactly when those two words are not Nerode-equivalent.

[L2]

By A language is regular if and only if its Nerode equivalence has finite index, a regular language has only finitely many Nerode classes.

Proof

technique · direct
1.1

If two words are pairwise distinguished by suffixes, then [L1] shows that they lie in distinct Nerode classes.

L1given
2.1

Therefore the infinitely many given words occupy infinitely many Nerode classes. By [L2], L cannot be regular.

L2step 1.1

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources