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CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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Every element outside Φ(P) belongs to a minimal generating set of P

Statement

Every element of PΦ(P) belongs to a minimal generating set of the finite p-group P.

Facts & Assumptions

[L1]

A subset XP is minimally generating exactly when the quotient map restricts to a bijection from X onto a basis of P/Φ(P) (Burnside Basis Theorem).

[L2]

Every independent subset of a finite elementary abelian p-group extends to a basis (Finite elementary abelian p-groups have bases, basis extension, and a well-defined dimension).

[L3]

For a finite p-group P, the quotient P/Φ(P) is elementary abelian (The Frattini quotient is the largest elementary abelian quotient of a finite p-group).

Proof

technique · direct
1.1

By [L3] the quotient P/Φ(P) is a finite elementary abelian p-group, so [L2] applies to it. The coset xΦ(P) is nonzero, so its singleton is independent in P/Φ(P).

givenL2L3algebra
2.1

Extend that singleton by [L2] to a finite basis. For every other basis vector choose one lift in P and adjoin it to x. The quotient map restricts to a bijection from this lifted set onto the basis, so [L1] makes it a minimal generating set containing x. The assertion is vacuous for P=1.

step 1.1L1L2given

Depends on

Used by

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Dependency tree · two levels

21 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources