Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-11
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A nontrivial finite abelian group is cyclic if and only if it has one invariant factor

Statement

A nontrivial finite abelian group is cyclic if and only if its invariant-factor list has exactly one entry.

Facts & Assumptions

Given: The objects and hypotheses in the statement.

[L1]

For every finite abelian group G there is a unique list 1<n1∣⋯∣nr such that G≅Cn1×⋯×Cnr. Moreover ∣G∣=n1⋯nr. The trivial group corresponds to the empty list and empty product. (Fundamental theorem of finite abelian groups: invariant-factor form).

[L2]

If G≅Cn1×⋯×Cnr with 1<n1∣⋯∣nr, then ∣G∣=n1⋯nr and exp⁡(G)=nr. For the empty list, ∣G∣=exp⁡(G)=1. (Invariant factors determine the order and exponent of a finite abelian group).

[L3]

If G=⟨g⟩ is cyclic, then exactly one of the following applies: - if g has infinite order, G≅(Z,+); - if g has finite order n, necessarily n≥1, then G≅(Z/n,+). (Every cyclic group is isomorphic to (Z,+) or to (Z/n,+) for its finite order n≥1).

Proof

technique · direct
1.1

A one-entry invariant-factor decomposition is an isomorphism with one cyclic group, so G is cyclic.

givenL1L2L3
2.1

Conversely a nontrivial finite cyclic group is isomorphic to C∣G∣, giving the one-entry list; uniqueness of invariant factors rules out any different list.

step 1.1∎

Depends on

Used by

Dependency tree · two levels

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Sources