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Finite C prime(1/6) presentations have solvable word problem
Statement
Every finite presentation has solvable word problem.
Facts & Assumptions
Given: A finite presentation satisfying .
Greendlinger's lemma provides, for every nonempty freely reduced null word, a relator subword longer than half of a defining relator (In a reduced C prime(1/6) null diagram, some face contributes more than half of its boundary to the outer boundary).
Every finite Dehn presentation has a terminating decision procedure for the word problem (Dehn's algorithm terminates and decides the word problem for a Dehn presentation).
Proof
By [L1], the given finite presentation is a Dehn presentation: every nonempty freely reduced trivial word contains the required long relator subword.
Apply [L2] to that Dehn presentation. The resulting Dehn algorithm decides triviality of words.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- GAP SmallCancellation manual, Chapter 1: Small Cancellation Theory — the classical conditions (standard reference, not scraped)
- Jay Williams, Universal Countable Borel Quasi-Orders (standard reference, not scraped)
- Nicholas Touikan, An Introduction to Combinatorial and Geometric Group Theory, Section 3.5 (standard reference, not scraped)
- Clara Löh, Geometric Group Theory: An Introduction, Section 7.4.1 (standard reference, not scraped)