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First Green identity
Statement
Assume . Let , , be a bounded domain or have the specified finite piecewise presentation. For real and , In the piecewise case the right side is the sum over faces, counted once off E. All integrals are finite.
Facts & Assumptions
Given: Assume , a bounded C1 domain or the specified finite piecewise C1 class in dimension , and real , .
The divergence formula holds for a C1 field up to a C1 boundary. (Divergence on a bounded C1 Euclidean domain).
The divergence formula holds for the specified finite faces. (Divergence for finite piecewise C1 presentations).
The normal derivative is the gradient dotted with the outward normal. (Classical normal derivative).
The product rule applies to scalar derivatives. (Sums, scalar multiples, products and quotients: , , , and when ).
Proof
Set . On each coordinate line inside Omega the product rule F4 gives ; the same rule for every shows that F and all its first derivatives extend continuously to the closure. Thus and summing over i gives .
On every regular boundary point F3 gives . Apply F1 in the C1 case and F2 in the specified piecewise case to the field from step 1.1. Substituting its divergence and flux gives exactly the displayed identity. Continuous derivatives and functions on the compact closure are bounded; finite volume and the finite surface measures in F1/F2 prove absolute integrability. The edge set contributes zero to each face integral.
Source notes
Hunter §2.5, Theorem 2.23, equation (2.11) and its proof, printed p. 32 (PDF p. 38); the weaker C1 assumption on v follows from the displayed product computation.
Depends on
- Divergence on a bounded C1 Euclidean domain
- Divergence for finite piecewise C1 presentations
- Classical normal derivative
- Sums, scalar multiples, products and quotients: $(f+g)'(c) = f'(c) + g'(c)$, $(\alpha f)'(c) = \alpha f'(c)$, $(fg)'(c) = f'(c)g(c) + f(c)g'(c)$, and $(f/g)'(c) = \bigl(f'(c)g(c) - f(c)g'(c)\bigr)/g(c)^{2}$ when $g(c) \ne 0$
Used by
- Second Green identity Corollary
Dependency tree · two levels
25 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Hunter, Notes on Partial Differential Equations (standard reference, not scraped)