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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
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First Green identity

Statement

Assume ACω. Let ΩRn, n2, be a bounded C1 domain or have the specified finite piecewise C1 presentation. For real uC2(Ω) and vC1(Ω), Ω(vΔu+DuDv)dx=ΩvνudS. In the piecewise case the right side is the sum over faces, counted once off E. All integrals are finite.

Facts & Assumptions

Given: Assume ACω, a bounded C1 domain or the specified finite piecewise C1 class in dimension n2, and real uC2(Ω), vC1(Ω).

[F1]

The divergence formula holds for a C1 field up to a C1 boundary. (Divergence on a bounded C1 Euclidean domain).

[F2]

The divergence formula holds for the specified finite faces. (Divergence for finite piecewise C1 presentations).

[F3]

The normal derivative is the gradient dotted with the outward normal. (Classical normal derivative).

Proof

1.1

Set Fi=viu. On each coordinate line inside Omega the product rule F4 gives iFi=(iv)(iu)+vi2u; the same rule for every jFi shows that F and all its first derivatives extend continuously to the closure. Thus FC1(Ω;Rn) and summing over i gives divF=DuDv+vΔu.

givenF4algebra
2.1

On every regular boundary point F3 gives Fν=v(Duν)=vνu. Apply F1 in the C1 case and F2 in the specified piecewise case to the field from step 1.1. Substituting its divergence and flux gives exactly the displayed identity. Continuous derivatives and functions on the compact closure are bounded; finite volume and the finite surface measures in F1/F2 prove absolute integrability. The edge set contributes zero to each face integral.

step 1.1F1F2F3algebra

Source notes

Hunter §2.5, Theorem 2.23, equation (2.11) and its proof, printed p. 32 (PDF p. 38); the weaker C1 assumption on v follows from the displayed product computation.

Depends on

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Sources