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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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Φ(P)=P2 for a finite 2-group

Statement

For every finite 2-group P, Φ(P)=P2.

Facts & Assumptions

Given: A finite 2-group P.

[L1]

For every finite p-group P, the subgroup Pp is characteristic and Φ(P)=P′Pp (Φ(P)=P′Pp for a finite p-group).

[F1]

The square subgroup is P2=⟨g2:g∈P⟩ (The pth-power subgroup Gp).

[L2]

For N⊴G, the quotient G/N is abelian if and only if G′≤N (G/N is abelian if and only if [G,G]⊆N).

Proof

technique · direct
1.1givenL1F1algebra

By [L1], P2 is characteristic and hence normal. Every element of P/P2 has square one by [F1]. In any group of exponent at most two, (xy)2=e gives xy=(xy)−1=y−1x−1=yx, so P/P2 is abelian.

2.1step 1.1L1F1L2algebra∎

By [L2], step 1.1 gives P′≤P2. Substituting in [L1] yields Φ(P)=P′P2=P2, including P=1.

Depends on

Used by

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources