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CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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Frobenius gives local first integrals

Statement

Let D be an involutive rank-k distribution on an n-manifold M. Then near every point there is a submersion F=(fk+1,,fn) onto an open set of Rnk such that

D=kerdF.

Equivalently, the functions fk+1,,fn are local first integrals for D.

Facts & Assumptions

Given: An involutive rank-k distribution D and a point pM.

[A1]

Choose Frobenius coordinates around p.

Proof

technique · direct
1.1

In Frobenius coordinates (x1,,xn), the distribution is spanned by [given] x1,,xk. Define F(x1,,xn):=(xk+1,,xn). Its differential has rank nk, so F is a submersion.

givenconstruct
1.2

A tangent vector lies in kerdF exactly when its last nk coordinate [given] components vanish, so precisely when it is a linear combination of x1,,xk. Hence kerdF=D.

givenalgebra
1.3

Therefore every involutive distribution is locally the common kernel of [given] nk smooth first integrals.

given

Depends on

Used by

Dependency tree · two levels

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Sources