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Frobenius gives local first integrals
Statement
Let be an involutive rank- distribution on an -manifold . Then near every point there is a submersion onto an open set of such that
Equivalently, the functions are local first integrals for .
Facts & Assumptions
Given: An involutive rank- distribution and a point .
Choose Frobenius coordinates around .
Proof
In Frobenius coordinates , the distribution is spanned by [given] . Define Its differential has rank , so is a submersion.
A tangent vector lies in exactly when its last coordinate [given] components vanish, so precisely when it is a linear combination of . Hence .
Therefore every involutive distribution is locally the common kernel of [given] smooth first integrals.
Depends on
Used by
Dependency tree · two levels
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Sources
- John M. Lee, Introduction to Smooth Manifolds, 2nd ed. (standard reference, not scraped)
- Will J. Merry, Differential Geometry (standard reference, not scraped)