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CorollaryStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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GLn(F)\operatorname{GL}_n(F) is a group under matrix multiplication, including the trivial group GL0(F)\operatorname{GL}_0(F)

Statement

For every field FF and natural nn, GLn(F)\operatorname{GL}_n(F) is a group under matrix multiplication. For n=0n=0, it is the trivial group containing the unique empty matrix.

Facts & Assumptions

Given: A field FF and a natural nn.

[L1]

GLn(F)\operatorname{GL}_n(F) is the set of invertible matrices, equivalently the units of Mn(F)M_n(F) (Invertible matrices and the general linear group GLn(F)\operatorname{GL}_n(F)).

Proof

technique · direct
1.1

By [L1], GLn(F)\operatorname{GL}_n(F) is exactly the unit set of the ring Mn(F)M_n(F).

givenL1
2.1

Applying [L2] gives closure, associativity inherited from the ring, identity InI_n, and inverse A1A^{-1} for every element, so GLn(F)\operatorname{GL}_n(F) is a group.

step 1.1L1L2
3.1

If n=0n=0, M0(F)M_0(F) has one element, the empty matrix I0I_0, which is its own inverse; hence its unit group is the trivial group.

step 2.1L1L2

Depends on

Used by

Nothing in the library uses this result yet.

Cited to discharge well-definedness by Invertible matrices and the general linear group GLₙ(F).

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 25 results over 14 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources