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CorollaryStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-02
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Every Hamiltonian graph on at least three vertices is 2-connected

Statement

Every Hamiltonian finite simple graph G with V(G)3 satisfies κ(G)2; equivalently, it is 2-connected.

Facts & Assumptions

Given: A Hamiltonian graph G on at least three vertices.

[F1]

A Hamiltonian graph has a cycle containing all its vertices and is connected (Hamilton paths, Hamilton cycles, Hamiltonian graphs and Hamilton-connected graphs).

[L1]

Deleting any nonempty proper vertex set S from a Hamiltonian graph leaves at most S components (If G has a Hamilton cycle, then deleting any nonempty proper vertex set S leaves at most S connected components).

[F2]

A vertex cut disconnects the graph or leaves at most one vertex, and κ(G) is the minimum size of a vertex cut (Vertex cuts, edge cuts, vertex connectivity κ(G) and edge connectivity λ(G), with conventions for complete and one-vertex graphs).

Proof

technique · direct
1.1

The graph G is connected by [F1]. For any vertex v, the set {v} is nonempty and proper, and Gv has at least two vertices. By [L1], it has at most one connected component, hence it is connected.

givenF1L1
2.1

Thus neither the empty set nor a singleton is a vertex cut: deleting nothing preserves connectedness, and deleting one vertex leaves a connected graph with at least two vertices.

step 1.1F2
3.1

Every vertex cut therefore has size at least two, so κ(G)2 by [F2].

step 2.1F2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 21 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources