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Tails of a convergent improper integral tend to zero
Statement
If converges, then Equivalently, for every all sufficiently remote proper tails have absolute value below . The corresponding tails tend to zero at and at either finite singular endpoint.
Facts & Assumptions
Given: A convergent one-ended improper integral of .
A convergent integral may be split at every finite truncation (Improper convergence is independent of finite truncations and split points).
Its proper remote tails satisfy the Cauchy criterion (Cauchy criterion for improper integrals).
Proof
Write . By [L1], , which tends to zero by the definition of .
The epsilon formulation is exactly [L2]. Reversing orientation or replacing infinite truncations by one-sided finite truncations proves all other stated forms.
Depends on
Used by
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Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 57 results over 14 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- William F. Trench, Introduction to Real Analysis, Section 3.4 (standard reference, not scraped)