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Integral extensions lift finite prime chains from the base
Statement
Assume the Axiom of Choice.
Let be an integral ring map, let
be a finite chain of prime ideals in , and let be a prime ideal of with . Then there exist prime ideals
of such that for every .
Facts & Assumptions
Given: An integral ring map , a finite prime chain in , and a prime of over .
Assuming the Axiom of Choice, the going-up theorem lifts one prime extension step at a time (Going up for integral ring maps).
Proof
For , the given prime already lifts the chain.
Fix and assume the statement for chains of length . Let be a chain of length . By the induction hypothesis, there are primes over .
Apply [L1] to the inclusion and the prime . This yields a prime with contraction .
Step 1.1 is the base case, and steps 1.2 and 2.1 provide the induction step. Therefore every finite prime chain in lifts to one in once the first prime upstairs is fixed.
Depends on
Used by
Dependency tree · two levels
4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. S. Milne, A Primer of Commutative Algebra, v4.03, Corollary 7.7 (standard reference, not scraped)
- Allen B. Altman and Steven L. Kleiman, A Term of Commutative Algebra, 13th ed., Theorem (14.3)(4) (standard reference, not scraped)