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Every irreducible representation of a finite group has degree at most
Statement
Let be a finite group and let be an irreducible representation of over a field . Then
Facts & Assumptions
Given: A finite group , a field , and an irreducible representation of over .
The group algebra has dimension over (If is finite then ).
The representation is a quotient of the regular representation (Every irreducible representation of a finite group is a quotient of the regular representation).
In a vector space with a spanning set of size , every linearly independent set has size at most (If has a spanning set with elements, then every linearly independent subset of is finite with at most elements; in particular has no linearly independent subset equinumerous with ).
The degree of a representation is the dimension of its underlying vector space, and that dimension is the size of any basis (A finite-dimensional representation over a field, and its degree, Finite-dimensional vector space, and its dimension ; infinite-dimensional means having no finite basis).
Proof
By [L2], there is a surjective linear map .
The images under of the basis vectors of span , so has a spanning set with elements by [L1].
Let be a basis of . Then is linearly independent, and step 2.1 together with [L3] shows that . By [L4], . Therefore .
Depends on
- If $G$ is finite then $\dim_k k[G]=|G|$
- If $V$ has a spanning set with $n$ elements, then every linearly independent subset of $V$ is finite with at most $n$ elements; in particular $V$ has no linearly independent subset equinumerous with $\mathbb{N}$
- Finite-dimensional vector space, and its dimension $\dim_F V$; infinite-dimensional means having no finite basis
- A finite-dimensional representation $\rho:G\to \operatorname{GL}(V)$ over a field, and its degree
- Every irreducible representation of a finite group is a quotient of the regular representation
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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Sources
- Peter Webb, A Course in Finite Group Representation Theory, Theorem 2.1.1 and regular-module consequences (standard reference, not scraped)