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Almost-everywhere convergence from the Carleson–Hunt estimate
Statement
Assume the Axiom of Choice and let . Every complex satisfies almost everywhere, with symmetric partial sums and normalized Haar measure on the period-one torus. The conclusion holds for every measurable representative of .
Facts & Assumptions
Given: The Axiom of Choice, , and the normalized torus conventions.
Under AC, a finite constant satisfies for every complex , where (Carleson hunt maximal inequality on the torus).
Under countable choice, a bound for all and all , with finite , implies almost everywhere for every , for every measurable representative (A weak maximal bound implies almost-everywhere Fourier convergence).
For nonnegative measurable and , (Chebyshev-Markov inequality for the integral).
The Axiom of Choice (The Axiom of Choice) implies countable choice and supplies the choice hypothesis of F1 and F2.
Proof
For and , F1 and F3 applied to at give . The maximal function and Fourier conventions in F1 agree with those in F2.
The weak estimate therefore holds for every and every positive threshold with finite . Since lies in the range of F2 and AC supplies countable choice, F2 proves the assertion for every and every measurable representative. The strong estimate is discharged by the local proved theorem F1.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Laugesen, Harmonic Analysis Lecture Notes (standard reference, not scraped)