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Almost-everywhere convergence from the Carleson–Hunt estimate

Statement

Assume the Axiom of Choice and let 1<p<∞. Every complex f∈Lp(T) satisfies SNf→f almost everywhere, with symmetric partial sums and normalized Haar measure on the period-one torus. The conclusion holds for every measurable representative of f.

Facts & Assumptions

Given: The Axiom of Choice, 1<p<∞, and the normalized torus conventions.

[F1]

Under AC, a finite constant Cp satisfies ∥Cg∥p≤Cp∥g∥p for every complex g∈Lp(T), where Cg=sup⁡N≥0∣SNg∣ (Carleson hunt maximal inequality on the torus).

[F2]

Under countable choice, a bound m{Cg>λ}≤Aλ−p∥g∥pp for all g∈Lp and all λ>0, with finite A≥0, implies SNf→f almost everywhere for every f∈Lp, for every measurable representative (A weak maximal bound implies almost-everywhere Fourier convergence).

[F3]

For nonnegative measurable h and t>0, m{h≥t}≤t−1∫h dm (Chebyshev-Markov inequality for the integral).

[F4]

The Axiom of Choice (The Axiom of Choice) implies countable choice and supplies the choice hypothesis of F1 and F2.

Proof

1.1F1F3given

For g∈Lp and λ>0, F1 and F3 applied to (Cg)p at t=λp give m{Cg>λ}≤λ−p∫(Cg)p dm≤Cppλ−p∥g∥pp. The maximal function and Fourier conventions in F1 agree with those in F2.

2.1F2F4step 1.1given∎

The weak estimate therefore holds for every g and every positive threshold with finite A=Cpp. Since 1<p<∞ lies in the range 1≤p<∞ of F2 and AC supplies countable choice, F2 proves the assertion for every f and every measurable representative. The strong estimate is discharged by the local proved theorem F1.

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