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Tensor products are unique up to a unique isomorphism carrying elementary tensors to elementary tensors
Statement
Let be abelian groups equipped with balanced maps and , and suppose that each pair has the universal property of Universal property of the tensor product for balanced maps into abelian groups. Then there is a unique group isomorphism such that . Its inverse is the unique map with .
Facts & Assumptions
Given: Two representing pairs and for balanced maps out of .
For any balanced map from into an abelian group, a representing pair supplies a unique group homomorphism through which that map factors (Universal property of the tensor product for balanced maps into abelian groups).
Proof
Apply [L1] for to the balanced map and for to ; this gives unique homomorphisms and with and .
Both and compose with to give , so uniqueness in [L1] gives ; similarly .
Thus is an isomorphism with inverse , and the same uniqueness clause shows that no other isomorphism carrying to exists.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 18 results over 7 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- Stacks Project, Section 10.12: Tensor products (standard reference, not scraped)