Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-16
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A modulus with primitive roots has exactly φ(φ(n)) primitive roots

Statement

If n≥1 admits a primitive root, then it has exactly φ(φ(n)) primitive roots.

Facts & Assumptions

Given: A positive modulus n admitting a primitive root.

[L1]

Primitive roots are exactly generators of the unit group (A unit is a primitive root modulo n if and only if it generates (Z/nZ)×).

Proof

technique · direct
1.1givenL1

By the Given and [L1], the unit group is cyclic of order φ(n), and its generators are exactly the primitive roots.

2.1step 1.1L2∎

Applying [L2] with m=φ(n) yields φ(φ(n)) primitive roots. At n=1 this is φ(1)=1, counting the unique class.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources