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The product of the invariant factors is the characteristic polynomial
Statement
If are the invariant factors of an endomorphism , then the product of the invariant factors is the characteristic polynomial:
On the zero space this is the empty product .
Facts & Assumptions
Given: The characteristic polynomial of The basis-independent characteristic polynomial of an endomorphism of a finite-dimensional space, including in dimension zero, the companion-matrix convention of The companion matrix of a monic polynomial, and multiplication of characteristic polynomials across block triangular matrices (The characteristic polynomial of a block upper- or lower-triangular matrix is the product of the characteristic polynomials of its diagonal blocks).
In rational canonical form, the blocks are the companion matrices of the invariant factors (Existence and uniqueness of rational canonical form).
Proof
Expanding along the companion rows gives the monic polynomial ; this includes zero coefficients and linear companion matrices.
By [L1], is similar to the block diagonal matrix with blocks . Characteristic polynomials are similarity-invariant and multiply over block diagonals, so step 1.1 gives . With no blocks, the determinant and product are both .
Depends on
- Existence and uniqueness of rational canonical form
- The basis-independent characteristic polynomial $\chi_T$ of an endomorphism of a finite-dimensional space, including $\chi_T=1$ in dimension zero
- The characteristic polynomial of a block upper- or lower-triangular matrix is the product of the characteristic polynomials of its diagonal blocks
- The companion matrix of a monic polynomial
Used by
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Sources
- A. Apisa, Wisconsin Math 542, Lemma 33 (standard reference, not scraped)
- M. Brussel, Finitely Generated Modules over a PID, Section 5.2 (standard reference, not scraped)