Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedprecheck passaudited 2026-08-13
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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P(X=0)≤Var⁡(X)/E[X]2 whenever E[X]≠0

Statement

If X is a finite real random variable with E[X]≠0, then P(X=0)≤Var⁡(X)E[X]2. Equivalently, P(X≠0)≥1−Var⁡(X)E[X]2.

Facts & Assumptions

Given: A finite real random variable X with E[X]≠0.

[L1]

Chebyshev gives P(∣X−E[X]∣≥t)≤Var⁡(X)/t2 for t>0 (Chebyshev's inequality on a finite probability space).

Proof

technique · direct
1.1

If X=0, then ∣X−E[X]∣=∣E[X]∣, and the latter is positive. Thus {X=0}⊆{∣X−E[X]∣≥∣E[X]∣}.

given
2.1

Apply [L1] at t=∣E[X]∣ and use t2=E[X]2 to obtain the first inequality.

step 1.1L1algebra
3.1

Taking complements gives the equivalent lower bound. The assumption E[X]≠0 is exactly what makes the threshold positive and the denominator nonzero.

step 2.1algebra∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources