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CorollaryStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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Squarefree sums of two squares

Statement

A squarefree positive integer is a sum of two squares if and only if none of its odd prime factors is congruent to 3 modulo 4; every such representation is primitive.

Facts & Assumptions

Given: A squarefree positive integer n.

[F1]

A positive integer n is squarefree if no square of a prime divides n; equivalently, every exponent in its canonical prime factorisation is 0 or 1 (Squarefree positive integers).

[L1]

A positive integer n is a sum of two squares if and only if every prime q3(mod4) occurs to an even exponent in its canonical prime factorisation (Characterisation of positive integers that are sums of two squares).

[L2]

A positive integer n has a primitive two-square representation if and only if v2(n)1 and no prime q3(mod4) divides n (Characterisation of primitive sums of two squares).

[F2]

An integer d is a common divisor of a and b when da and db (Common divisor, and the greatest common divisor gcd(a,b), with the convention gcd(0,0):=0).

[L4]

If a prime p divides ab, then pa or pb (Euclid's lemma: if p is prime and pab then pa or pb).

Proof

technique · direct
1.1

By [F1], every prime exponent of n is zero or one. Consequently the even-exponent condition in [L1] for a prime congruent to three modulo four is equivalent to that prime not dividing n.

F1L1algebra
1.2

To see that every representation is primitive, suppose n=x2+y2 and gcd(x,y)>1. By [L3] choose a prime dividing the gcd. Then x and y by [F2], so 2n, contradicting [F1].

F1F2L3L4assume-contraalgebradischarge-contradiction
2.1

Squarefreeness also gives v2(n)1, so the same exclusion of three-mod-four primes satisfies [L2] and yields a primitive representation whenever n is represented.

step 1.1L2F1
3.1

Step 1.1 proves the representation criterion, step 2.1 supplies primitivity under that criterion, and step 1.2 shows that every representation has it.

step 1.1step 2.1step 1.2

Depends on

Used by

Dependency tree · two levels

36 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources