Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-21
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Zero is a subgradient exactly at a global minimum

Statement

Let f:C→R be convex and let a∈C. Then 0∈∂f(a) if and only if f(a)≤f(y) for every y∈C.

Facts & Assumptions

Given: The function and point in the Statement.

[F1]

A vector v is a subgradient of f at a when f(y)≥f(a)+⟨v,y−a⟩ for every y in the domain (Subgradients and the subdifferential of a convex function).

Proof

technique · direct
1.1F1algebra

For the forward implication, put v=0 in [F1]. The result is f(y)≥f(a) for every y∈C, exactly the global-minimum condition.

2.1F1assume-hyp∎

For the reverse implication, if a is a global minimizer then f(y)≥f(a)=f(a)+⟨0,y−a⟩ for every y. This is [F1] with v=0, so 0∈∂f(a).

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources