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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
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Tori correspond exactly to torsion-free character lattices

Statement

Assume the Axiom of Choice. A finite-type group of multiplicative type over any field is a torus if and only if its character module is torsion-free, equivalently a free abelian group of finite rank. Thus the classification restricts to an anti-equivalence between k-tori and free finite-rank abelian groups with continuous Galois action. A multiplicative group with nonzero torsion in its character module is not a torus, even when it is smooth.

Facts & Assumptions

[A1]

Assume The Axiom of Choice; it is used through the general multiplicative-type classification, whose affineness interface uses fpqc submersiveness.

[F2]

Characters and products in the split case are Split diagonalizable groups are dual to abelian groups.

[F3]

Tori are defined by splitting into a finite product of multiplicative groups: Groups of multiplicative type and tori.

Proof

Given: G of multiplicative type and M=X∗(G).

1.1givenalgebra

A finitely generated abelian group admits a finite presentation: for a surjection Zd→M, its kernel is finitely generated by induction on d, projecting to the last coordinate, whose image is cyclic; lift a generator of that image and use the induction hypothesis for the kernel of the projection. For its integer relation matrix, integer row and column operations give diagonal form. Specifically move a nonzero entry of smallest positive absolute value to the first position and divide entries in its row and column by it with remainder. A nonzero remainder lowers that pivot, so this process terminates. If the pivot does not divide an entry of the remaining block, add the row containing that entry to the pivot row and repeat the division; again the pivot decreases. Thus it eventually divides the whole block, its row and column can be cleared, and induction diagonalizes the smaller block. These invertible operations yield M≅Zr⊕⨁iZ/niZ, with ni>1 after removing unit entries. Consequently M is torsion-free exactly when it is free of finite rank.

2.1A1F1F2F3step 1.1algebra∎

If M is free of rank r, F1 and F2 give Gks≅Dks(M)≅Gmr, so G is a torus. Conversely, if GK≅Gmr for some extension K/k, choose a finite Galois splitting field L/k from F1. The finite-dimensional nonzero K-algebra L⊗kK has a maximal ideal: select a proper ideal of largest vector-space dimension. Its residue field E contains both L and K, since the maps from these fields are unital. Base change of the splitting isomorphism GL≅DL(M) to E identifies GE with DE(M), so F2 computes X∗(GE)=M, while base change of GK≅Gmr computes that same module as Zr. Hence M≅Zr and is torsion-free. The natural bijections of F1 restrict to these objects, proving the asserted equivalence and the exclusion of every nonzero torsion module.

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Sources