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Amalgamation over the trivial group is the ordinary free product
Statement
The free product with amalgamation over the trivial group is canonically isomorphic to the ordinary free product.
Facts & Assumptions
Given: The objects and hypotheses in the statement.
If and are injective homomorphisms, their pushout is called the free product with amalgamation and is denoted . The quotient construction is thm-group-pushout-as-an-amalgamated-quotient, and injectivity means the trivial-kernel condition of thm-group-homomorphism-injective-iff-trivial-kernel. The notation anticipates identifying with its two images, but injectivity of the canonical maps is a theorem, not part of this definition. (Free products with amalgamation along monomorphisms).
For a family , a free product is a group with homomorphisms in the sense of def-group-homomorphism, such that for every group and every family of homomorphisms , there is a unique homomorphism satisfying for all . It is denoted . Injectivity of the maps is not part of this definition. (The free product of an arbitrary family of groups).
Any two free products of the same family are connected by a unique isomorphism commuting with every canonical factor map. (Free products are unique up to a unique factor-compatible isomorphism).
Proof
For maps from the trivial group, the compatibility equation in the pushout property is automatic.
Thus the amalgamated pushout and the ordinary free product satisfy the same universal property, and uniqueness supplies the canonical isomorphism. Trivial factors cause no exception.
Depends on
Used by
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Sources
- George D. Torres, Combinatorial Group Theory, §2 (standard reference, not scraped)
- B. H. Neumann, Lectures on Topics in the Theory of Infinite Groups, Ch. 9 (standard reference, not scraped)