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CorollaryStatement: AI-adaptedProof: AI-adaptedprecheck passaudited 2026-08-13
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A square root of −1 in a real field extension determines a unique real-field homomorphism from C

Statement

Let L/R be a field extension and let j∈L satisfy j2=−1. There is a unique field homomorphism C→L fixing R and sending i to j. Its image is R[j].

Facts & Assumptions

Given: A real field extension L/R and j∈L with j2=−1.

[F1]

The complex numbers are R[x]/(x2+1) with i=x+(x2+1) (The complex numbers as R[x]/(x2+1), with the real embedding and imaginary unit i).

[F2]

x2+1 is monic and irreducible over R (x2+1 is irreducible over R).

[F3]

In a quotient adjoining a root of a monic irreducible polynomial, any root in an extension determines a unique base-field homomorphism, whose image is the generated subring (Universal property of adjoining a root of an irreducible polynomial).

Proof

technique · direct
1.1

The equation j2=−1 says exactly that j is a root of x2+1.

algebra
2.1

Apply [F3] to [F1], [F2], and step 1.1. It gives the unique homomorphism fixing R, sending i to j, and having image R[j].

F1F2F3step 1.1∎

Depends on

Used by

Dependency tree · two levels

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Sources