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CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-24
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A right circular cone of radius R and height h has volume πR2h/3

Statement

A right circular cone of radius R0 and height h0 has volume πR2h/3.

Facts & Assumptions

Given: Nonnegative reals R,h and a right circular cone.

[F1]

A solid of revolution with profile f has volume πabf(x)2dx (The disc formula for the volume of a solid of revolution).

[F2]

If an integrable function is a derivative G on [a,b], then its integral is G(b)G(a) (The second fundamental theorem: if G is differentiable on [a,b] with G=f and f is integrable, then abf=G(b)G(a)).

Proof

technique · direct
1.1

If h=0 or R=0, the cone is degenerate and both sides are zero. Otherwise apply [F1] to f(x)=Rx/h on [0,h].

givenF1cases
2.1

The function G(x)=πR2x3/(3h2) has derivative πR2x2/h2, so [F2] evaluates the volume as G(h)G(0)=πR2h/3.

step 1.1F2algebra
3.1

The positive-height computation and the zero-parameter case together prove the formula for all R,h0.

step 1.1step 2.1cases-exhaustive

Depends on

Used by

Dependency tree · two levels

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Sources