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DefinitionDefinition: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck pendingjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite stochastic shortest-path problems

Definition

Let a finite MDP have nonempty finite state set S and finite nonempty action sets A(s). A finite stochastic shortest-path problem consists of that MDP, a nonempty goal set G⊆S, and a constant cmin⁡>0 with the following properties. Each goal g∈G has exactly one available action ag, and its joint reward-transition law satisfies p(g,0∣g,ag)=1 (so 0∈R). For every s∉G and every a∈A(s), the expected reward satisfies r(s,a)≤−cmin⁡. Define the one-step expected cost by c(s,a)=−r(s,a) off G and c(g,a)=0 at goals. A stationary Markov policy π is proper if, from every initial state, the finite-step probabilities of not having reached G tend to 0: with q0(s)=1s∉G and

qn+1(s)=∑a∈A(s)π(a∣s)∑s′∈SP(s′∣s,a)qn(s′)(s∉G),qn+1(g)=0(g∈G),

properness means qn(s)→0 for every s∈S. The problem need not have a proper policy unless that is separately assumed.

Facts & Assumptions

Given: A finite MDP, nonempty goal set G, absorbing zero-reward dummy actions at goals, and the strict negative expected-reward bound on every nonglobal state-action pair in the Definition.

[F1]

Finite Markov decision process with joint reward-transition law: each A(s) is finite and nonempty; P(⋅∣s,a) is a probability distribution obtained by marginalizing the joint reward-transition law, and r(s,a) is its expected one-step reward.

Verification

Given: The finite MDP data and a stationary Markov policy π.

1.1givenF1algebra

The expected costs c(s,a)=−r(s,a) are finite because the reward alphabet is finite and the joint row is a probability mass by [F1]. The stated reward bound gives c(s,a)≥cmin⁡>0 off G, and the dummy action at each goal has cost 0.

2.1givenF1step 1.1algebra∎

By [F1], every row P(⋅∣s,a) is a probability distribution, and every policy row π(⋅∣s) is a probability distribution. Thus the recursion defining qn+1 is a finite sum of nonnegative terms. If 0≤qn≤1, then 0≤qn+1(s)≤∑aπ(a∣s)∑s′P(s′∣s,a)=1 off G, while qn+1(g)=0 on G. Since q0∈[0,1]S, induction shows every qn is well-defined and lies in [0,1]S.

Depends on

Used by

Dependency tree · two levels

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Sources