Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedprecheck passaudited 2026-08-29
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A short floating-point dot product obeys the gamma_n error bound

Example

Take x=(1,2), y=(3,4) and the binary64 unit roundoff u=253, for which γ2=2u/(12u)2.21016. The left-to-right computed dot product s2 satisfies

s2=3(1+δ0)+8(1+δ1)with δ0,δ1γ2,

so the computed value is the exact dot product of slightly perturbed summands, and

s211    γ2(3+8)=11γ2    γ2x1y1=21γ24.71015.

Facts & Assumptions

Given: The vectors x=(1,2), y=(3,4), the exact dot product xy=11, the unit roundoff u=253 with 2u<1, and the left-to-right computed sum s2 of the two products x0y0=3 and x1y1=8.

[L1]

The computed dot product obeys the componentwise form sn=j<nxjyj(1+δj) with δjγn=nu/(1nu), and the normwise bound snxyγnjxjyjγnx1y1 (The computed floating-point dot product obeys componentwise and normwise error bounds).

Verification

technique · direct
1.1

With n=2 and 2u<1, [L1] applies and yields s2=x0y0(1+δ0)+x1y1(1+δ1) with δ0,δ1γ2, which for x=(1,2) and y=(3,4) reads s2=3(1+δ0)+8(1+δ1).

L1algebra
1.2

The exact dot product is xy=13+24=11, and the absolute summand total is x0y0+x1y1=3+8=11, while x1y1=(1+2)(3+4)=21.

algebra
2.1

By the normwise bound of [L1] applied to the numbers of step 1.2, s211γ211γ221; substituting u=253 gives γ2=252/(1252), so s21111252/(1252), a bound of order 1015.

L1step 1.2algebra
3.1

Step 1.1 verifies the componentwise perturbation form and step 2.1 the normwise bound for this short vector pair: the computed dot product agrees with the exact dot product of slightly perturbed summands and lies within 11γ2 of 11.

step 1.1step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources