Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A reductive algebra with degenerate Killing form

Example

For n1 over a characteristic-zero field, gln is reductive but its Killing form is degenerate:

gln=kIsln,K(I,X)=0(Xgln).

Facts & Assumptions

Given: The matrix Lie algebra gln(k), n1, over a characteristic-zero field.

[L1]

A finite-dimensional Lie algebra is reductive when it is the direct sum of its center and a semisimple ideal (Equivalent characterizations of reductive Lie algebras).

[L2]

Its Killing form is K(X,Y)=tr(adXadY) (Killing form).

Verification

technique · direct
1.1

Since n is invertible in k, every matrix has the unique decomposition X=trXnI+(XtrXnI), whose second term is traceless. Thus gln=kIsln. The first summand is the center and the second is semisimple for n2; for n=1 it is zero, which is semisimple by convention. Hence [L1] makes gln reductive for every n1.

L1givenalgebra
2.1

Since I is central, adI=0. Therefore [L2] gives K(I,X)=0 for every X. The nonzero vector I lies in the radical of the form, so it is degenerate; at n=1 it is identically zero. The calculation is finite and uses no choice.

L2step 1.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources