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ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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A uniformly integrable family need not admit a single integrable majorant

Example

On [0,1] with Lebesgue measure, define ak:=∑j=1k−112j2,Ik:=[ak,ak+12k2),fk:=k χIk.

Then the family (fk)k≥1 is uniformly integrable, but no integrable function dominates all of it almost everywhere.

Facts & Assumptions

Given: Lebesgue measure on [0,1], the intervals Ik, and the functions fk:=k χIk.

[L1]

Uniform integrability means that for every ε>0 there is M>0 such that ∫{∣fk∣>M}∣fk∣ dμ<ε for every k. (A uniformly integrable family)

[L2]

On finite measure spaces, uniform integrability is equivalent to L1-boundedness plus uniform absolute continuity. (On a finite measure space, uniform integrability is equivalent to L^1-boundedness plus uniform absolute continuity)

Verification

technique · direct
1.1givenalgebra

The series ∑k=1∞12k2 converges to a value below 1, so the intervals Ik are pairwise disjoint subsets of [0,1]. Also ∫∣fk∣ dλ=kλ(Ik)=12k.

2.1step 1.1L1algebra

If M>0 and k≤M, then {∣fk∣>M}=∅; if k>M, then {∣fk∣>M}=Ik and ∫{∣fk∣>M}∣fk∣ dλ=12k≤12⌊M⌋+2. Hence the family is uniformly integrable by [L1].

2.2step 1.1algebra

If g were an integrable majorant for all fk, then ∣g∣≥g≥k almost everywhere on Ik. Since the intervals are pairwise disjoint, ∫∣g∣ dλ≥∑k=1∞∫Ik∣g∣ dλ≥∑k=1∞12k=+∞, contradicting integrability of g.

3.1step 2.1step 2.2L2∎

This family is therefore uniformly integrable but has no single integrable majorant. The example is exactly the failure of the false statement paired with [L2].

Depends on

Used by

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Dependency tree · two levels

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