Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A2 coinvariant algebra and basic invariants

Example

Let S3 act by permuting coordinates on V={(x,y,z)C3:x+y+z=0}, the A2 reflection plane. Put e2=xy+xz+yz and e3=xyz restricted to V. Then C[V]S3=C[e2,e3],dege2=2,dege3=3. The coinvariant algebra has basis 1,x,y,x2,xy,x2y, Hilbert series 1+2t+2t2+t3, and dimension 6.

Facts & Assumptions

Given: The displayed permutation action and restricted elementary symmetric polynomials.

[F1]

A faithful finite reflection group has a polynomial invariant algebra and a free polynomial module of rank its order (Chevalley shephard todd for finite weyl groups).

[F2]

Invariants, the positive invariant ideal, and Reynolds averaging use the conventions of Finite linear invariant and coinvariant polynomial algebras.

Verification

1.1

Each transposition fixes a line in V and has eigenvalue 1 on the vector that subtracts its two exchanged coordinates. These transpositions generate S3. The action is faithful: a permutation fixing all coordinate differences fixes their labels and hence is identity. Thus F1 applies to this two-dimensional reflection representation. Eliminate z=xy to identify its polynomial algebra with C[x,y] and obtain e2=(x2+xy+y2) and e3=xy(x+y).

F1given
2.1

We verify generation directly. Any invariant polynomial on the plane has a polynomial lift to C[x,y,z]; average its six permuted lifts. By F2 its restriction is unchanged and the resulting lift is symmetric. A symmetric homogeneous polynomial in three variables is a polynomial in e1=x+y+z,e2,e3: use lexicographic order x>y>z on its finitely many monomials of fixed total degree. A leading exponent triple (a,b,c) satisfies abc, because swapping an out-of-order pair would produce a larger monomial with the same coefficient. The polynomial e1abe2bce3c has leading monomial xaybzc with coefficient one. Subtract its required multiple and repeat; lexicographic order strictly decreases within a finite set. Sum over the finitely many homogeneous parts. Restricting e1=0 proves invariant generation by e2,e3.

F2step 1.1
3.1

These generators are algebraically independent without an appeal to a degree table. Their Jacobian determinant in (x,y) is (2x+y)(x+2y)(xy), a nonzero polynomial. If a nonzero relation of least positive total degree H(e2,e3)=0 existed, differentiating it twice, once in each coordinate, and multiplying by the adjugate Jacobian matrix would give that determinant times each evaluated partial derivative of H is zero. The polynomial ring is a domain, so both evaluated derivatives vanish. In characteristic zero some partial derivative of a nonconstant H is nonzero and has lower degree, a contradiction; a nonzero constant cannot be a relation. Thus the stated invariant polynomial algebra has basic degrees two and three.

step 1.1step 2.1
4.1

By 2.1 and 3.1, the positive invariant ideal in F2 generates (e2,e3) in C[x,y]. Put a=y2+xy+x2 and b=xy(x+y). The identity xab=x3 gives (a,b)=(a,x3). First quotient by x3: with A=C[x]/(x3), the remaining quotient is A[y]/(y2+xy+x2). Division by this monic polynomial in y has unique remainder u+vy with u,vA. Existence follows by canceling the highest power of y; uniqueness follows because a nonzero multiple of a monic degree-two polynomial has degree at least two, even over A. The unique representatives of elements of A have degrees at most two in x. Hence 1,x,x2,y,xy,x2y are independent and spanning, proving the asserted basis and Hilbert series by their degrees 0,1,2,1,2,3.

F2step 2.1step 3.1
5.1

The quotient dimension is therefore 6=S3, matching the free rank in F1, and the degree product is 23=6. The degree-zero class is nonzero, the top class x2y is nonzero by unique remainder, and all degrees above three vanish. This is an explicit calculation on the nonzero two-dimensional plane; there is no limiting parameter or choice assumption.

F1step 4.1

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