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ExampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-07-31
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The alternating harmonic series illustrates Abel's boundary-limit theorem without evaluating its sum

Statement

Let ss denote the ordinary sum of the alternating harmonic series

s:=n=0(1)nι(n+1).s:=\sum_{n=0}^{\infty}\frac{(-1)^n}{\iota(n+1)}.

Then, without evaluating ss,

limx1n=0(1)nxnι(n+1)=s.\lim_{x\uparrow1}\sum_{n=0}^{\infty}\frac{(-1)^nx^n}{\iota(n+1)}=s.

Verification

technique · direct
1.1

By [L1], the ordinary sum ss exists.

L1
2.1

Apply [L2] to its coefficients an=(1)n/ι(n+1)a_n=(-1)^n/\iota(n+1) to obtain the displayed limit. No closed-form evaluation of ss is needed.

step 1.1L2

Depends on

Used by

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