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A randomized UMP test for a binomial model

Example

Assume AC. Let X=(X1,X2,X3)∈{0,1}3 have mass function Pp(X=x)=pT(x)(1−p)3−T(x) for 0<p<1, where T(x)=x1+x2+x3. For H0:p≤12 against H1:p>12, the randomized test with rejection function ϕ(x)=1{T(x)>2}+131{T(x)=2} is UMP of level α=14.

Verification

Given: The finite experiment and hypotheses in the statement.

[F1] In a family with MLR in T, the upper boundary-randomized threshold test calibrated at p0 is UMP for p≤p0 versus p>p0. (The Karlin–Rubin theorem for one-sided tests)

[F2] A randomized test is a binary-action probability kernel; its test function is a measurable rejection probability in [0,1]. (Randomized tests)

[F3] MLR means the likelihood ratio for every larger parameter is nondecreasing in T, including the extended-ratio support convention. (Families with a monotone likelihood ratio)

[F4] The size of a test is the supremum of its null rejection probabilities, and level α means that size is at most α. (Test size and power)

[F5] A probability kernel assigns a probability measure to each observation and has measurable event-evaluation functions. (Measure kernel and probability kernel)

1.1givenalgebra

The sample space has eight points, and ∑x∈{0,1}3pT(x)(1−p)3−T(x)=(p+(1−p))3=1, so the masses define a probability law; the statistic T is measurable on the finite power-set space.

1.2givenF3algebra

For 0<p1<p2<1, the likelihood ratio is p2T(x)(1−p2)3−T(x)p1T(x)(1−p1)3−T(x)=(1−p21−p1)3(p2(1−p1)p1(1−p2))T(x). The second base exceeds one since p2(1−p1)−p1(1−p2)=p2−p1>0, so the ratio increases with T and [F3] applies.

1.3givenF2F5algebraconstruct

At p0=1/2, each point has mass 1/8, with one point at T=3 and three at T=2; hence P1/2(T>2)=1/8 and P1/2(T=2)=3/8. The threshold c=2,γ=1/3 therefore has endpoint-null rejection probability 1/8+(1/3)(3/8)=1/4. Define K(x,B)=ϕ(x)1{1∈B}+(1−ϕ(x))1{0∈B} for B⊆{0,1}. The two weights are nonnegative and sum to one, and the formula is countably additive because each point belongs to at most one event in a disjoint sequence, so each section is a probability measure. Every event evaluation is measurable because the sample space is finite with its full sigma-algebra. Thus [F5] gives a probability kernel and [F2] makes it a randomized test with rejection function ϕ.

2.1F1F4step 1.2step 1.3∎

By step 1.2 the family has MLR in T, and step 1.3 calibrates the upper boundary-randomized threshold at p0=1/2 to α=1/4. The Karlin–Rubin result [F1] therefore makes this test UMP of level 1/4 for H0:p≤1/2 versus H1:p>1/2, with size and level interpreted by [F4].

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