Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A second-order normal system

Example

For analytic g,h, the equation utt=uxx with data u(0,x)=g(x), ut(0,x)=h(x) is equivalent to ut=v, vt=wx, wt=vx, with data (u,v,w)(0,x)=(g,h,g).

Facts & Assumptions

Given: The equation utt=uxx, its two analytic Cauchy data, and the three proposed jet variables of the Example.

[F1]

The compatible first-order jet system has an analytic solution recovering the scalar equation. (Reduction of higher-order normal form with jet compatibility).

Verification

1.1

For an analytic scalar solution put v=ut,w=ux. Then ut=v, vt=utt=uxx=wx and wt=uxt=utx=vx, with traces (g,h,g). These are precisely the m=2 equations of F1.

givenF1algebra
2.1

Conversely F1 supplies an analytic system solution. Its error e=wux satisfies et=vxxv=0 and e(0,x)=g(x)g(x)=0, so e is identically zero. Thus utt=vt=wx=uxx and ut(0,x)=h. For g=x2,h=1, the explicit solution is u=x2+t2+t, v=2t+1,w=2x: both vt and wx equal 2, and both wt and vx equal 0.

step 1.1F1algebra

Source notes

Gantumur, §4 Corollary 20 and equations (55)–(57), printed p. 11; scalar wave specialization computed locally.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources