Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-09-01
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Cb(X) is Banach for the supremum norm

Example

Let X be a nonempty topological space, and let Cb(X) be the space of bounded continuous scalar-valued functions on X with norm ∥f∥∞:=sup⁡x∈X∣f(x)∣. Then Cb(X) is a Banach space.

Facts & Assumptions

Given: A nonempty topological space X and a Cauchy sequence (fm) in Cb(X) for the supremum norm.

[L2]

A Banach space is a normed space complete for its norm metric (Banach space).

Verification

technique · direct
1.1givenconstruct

For each x∈X, the scalar sequence (fm(x))m is Cauchy because ∣fm(x)−fℓ(x)∣≤∥fm−fℓ∥∞. Define f(x):=lim⁡mfm(x).

2.1step 1.1given

Choose M with ∥fm−fℓ∥∞<1 for m,ℓ≥M. Fixing ℓ=M and letting m→∞ pointwise gives ∣f(x)∣≤∥fM∥∞+1 for every x, so f is bounded.

2.2step 1.1givenL1

Given ε>0, choose M with ∥fm−fℓ∥∞<ε for m,ℓ≥M. Letting ℓ→∞ pointwise yields ∥fm−f∥∞≤ε for m≥M. Thus fm→f uniformly, and [L1] makes f continuous.

3.1step 2.1step 2.2L2∎

So every supremum-norm Cauchy sequence in Cb(X) converges in Cb(X), and [L2] shows that Cb(X) is Banach.

Depends on

Used by

Dependency tree · two levels

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Sources