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Infinite dihedral growth, the infinite Steinberg identity, and the failure of polynomial reciprocity

Example

Let W=⟨s,t∣s2=t2=1⟩ be the infinite dihedral Coxeter group, so S={s,t} and m(s,t)=∞ (Coxeter matrices, the presented Coxeter group, reduced words, length, and standard parabolic subgroups, The rank-two block computation, exact dihedral orders, the signed reflection action, and ambient reducedness (3)(c),(4)). Then:

(1) Growth series. Every word reduces by canceling adjacent equal generators to an alternating word. For each q≥1, the two alternating words (st)q and (ts)q have length 2q; for each q≥0, (st)qs and (ts)qt have length 2q+1. These words are reduced by The rank-two block computation, exact dihedral orders, the signed reflection action, and ambient reducedness (7), with the generators interchanged for the words beginning with t; their pairwise distinctness is proved in step 1.1 below using the infinite order of st from (4). They exhaust the nonidentity elements, so W has one element of length 0 and exactly two of each length n≥1: PW(t)=1+2t+2t2+2t3+⋯=1+2t1−t=1+t1−t∈Q(t) The coefficientwise identity (1−t)PW=1+t follows from the displayed coefficients by the Cauchy product (Formal power series over a commutative ring and the coefficient-extraction functional [xn]), and 1−t has unit constant term (A formal power series is a unit exactly when its constant coefficient is a unit, Rational formal power series, proper presentations and reduced denominators).

(2) The infinite Steinberg identity. The spherical subsets are ∅,{s},{t}, with PW∅=1, PW{s}=PW{t}=1+t, and PW=(1+t)/(1−t); the infinite case of Finite descent parabolics, parabolic factorization, the Steinberg inclusion-exclusion identity, and rational growth (4) reads 1−21+t+1−t1+t=0, i.e. 1/PW(t)=1−t1+t, as the formal inverse of (1+t)/(1−t) requires (A formal power series is a unit exactly when its constant coefficient is a unit).

(3) Failure of polynomial reciprocity. The reduced words in (1) have unbounded lengths, so W has no longest element; the infinite-case result of Finite descent parabolics, parabolic factorization, the Steinberg inclusion-exclusion identity, and rational growth (1) also gives that no element has all descents. For comparison, the finite-case pattern tNPW(t−1)=PW(t) is the reciprocity of The Poincare polynomial as a product of q-integers of the basic degrees, with longest-element reciprocity (2). Here the rational function satisfies PW(t−1)=1+t−11−t−1=−1+t1−t=−PW(t). Thus, for every N≥0, tNPW(t−1)=−tNPW(t); equality with PW(t) would force tN=−1 in Q(t), which is impossible. The substitution is interpreted in the rational-function field, not as an element of Z⟦t⟧. More generally, an infinite Coxeter group with finite S has unbounded length (there are only finitely many words of bounded length), so its growth series is not a polynomial and the finite reciprocity theorem does not apply as a polynomial statement. This alone makes no assertion about rational-function reciprocity for other infinite Coxeter systems.

(4) Rank-one comparison. The parabolic W{s}={1,s} has PW{s}(t)=1+t=[2]t. The infinite growth series is not a finite product [m]t[2]t for any finite m, since every such product is a polynomial while PW has infinitely many nonzero coefficients. With the conventions of the companion page, this same group is denoted I2(∞).

Facts & Assumptions

Given: The presented group W=⟨s,t∣s2=t2=1⟩, the Coxeter matrix with m(s,t)=∞ on S={s,t}, its length function ℓ, and the series PA(t)=∑w∈Atℓ(w) of Length generating series, descent-class series, spherical subsets, and the multivariate descent polynomial.

[L1]

For m(s,t)=∞ the rank-two product st has infinite order in W and the elements s,t∈W are distinct involutions (The rank-two block computation, exact dihedral orders, the signed reflection action, and ambient reducedness (3)(c),(4)).

[L2]

Every alternating word beginning with either s or t of length q≥1 is reduced in the ambient group (apply the source also with s,t interchanged) (The rank-two block computation, exact dihedral orders, the signed reflection action, and ambient reducedness (7)).

[L3]

The defining relators s2=t2=1 allow adjacent equal letters to be canceled without changing the represented element; ℓ(w) is the minimum length of a generator word representing w (Coxeter matrices, the presented Coxeter group, reduced words, length, and standard parabolic subgroups).

[L4]

For every A⊆W the series PA=∑w∈Atℓ(w) is well-defined (Length generating series, descent-class series, spherical subsets, and the multivariate descent polynomial (1)); a series is rational if QF=P for polynomials with Q(0) a unit (Rational formal power series, proper presentations and reduced denominators).

[L5]

For J⊆S, WJ={w:ℓ(ws)>ℓ(w) for all s∈J} and PW=PWJPWJ (Finite descent parabolics, parabolic factorization, the Steinberg inclusion-exclusion identity, and rational growth (2)).

[L6]

For infinite W, ∑K⊆S(−1)∣K∣/PWK(t)=0 (Finite descent parabolics, parabolic factorization, the Steinberg inclusion-exclusion identity, and rational growth (4)).

[L8]

The finite-case pattern is tNPW(t−1)=PW(t) with N=ℓ(w0) (The Poincare polynomial as a product of q-integers of the basic degrees, with longest-element reciprocity (2)); its longest-element reciprocity argument is choice-free and its basic-degree branch is not used here.

[L9]

The Cauchy product is defined coefficientwise by finite sums, and a series with unit constant term has a unique formal inverse; here 1+t and (1+t)/(1−t) have constant term 1 (Formal power series over a commutative ring and the coefficient-extraction functional [xn], A formal power series is a unit exactly when its constant coefficient is a unit).

Verification

technique · direct
1.1L1L2L3L4L9algebra

Every word in s,t can be shortened by canceling an adjacent pair ss or tt by [L3], so a shortest word is alternating. For each q≥1 the two alternating words of length 2q are (st)q,(ts)q, and for each q≥0 the two of length 2q+1 are (st)qs,(ts)qt. They are reduced by [L2], so unequal lengths give unequal elements. Put r=st, so ts=r−1 and t=r−1s. At the same even length 2q>0, equality of the two words would give rq=r−q and hence r2q=1; at the same odd length 2q+1, equality would give rqs=r−qt=r−q−1s and hence r2q+1=1. Both contradict the infinite order in [L1]. Equivalently, the presentation admits the parity homomorphism sending both generators to −1, because each defining relator has even length, so even and odd words cannot coincide. Every element has one of these forms or is the identity. Thus [t0]PW=1 and [tn]PW=2 for every n≥1. By the Cauchy-product definition, (1−t)PW=1+t: its coefficients are 1 at degree 0, 2−1=1 at degree 1, and 2−2=0 at every degree n≥2. Since 1−t has unit constant term, PW=(1+t)/(1−t) in Z⟦t⟧, and [L4] makes this a rational series.

2.1step 1.1L1L6algebra

A subset I⊆S is spherical exactly when WI is finite. The three proper parabolics W∅={1}, W{s}={1,s} and W{t}={1,t} are finite; WS=W is infinite by [L1]. Thus the spherical subsets are exactly ∅,{s},{t}, with PW∅=1 and PW{s}=PW{t}=1+t, while all four subsets occur in the Steinberg sum of [L6]. Substituting PW=(1+t)/(1−t) from step 1.1 gives 1−2/(1+t)+1/PW=1−2/(1+t)+(1−t)/(1+t)=0, the infinite case of [L6].

2.2step 1.1L1L7L8algebra

In Q(t), PW(t−1)=(1+t−1)/(1−t−1)=−PW(t). If tNPW(t−1)=PW(t) for some N≥0, then −tNPW(t)=PW(t); since PW≠0, this forces tN=−1, impossible in Q(t). Thus no such N exists. The alternating words in step 1.1 have unbounded lengths, so W has no longest element; the infinite-case statement of [L7] also says no element has all descents.

3.1step 1.1step 2.1L4L9algebra

The series PW=(1+t)/(1−t) and (1−t)/(1+t) are inverse to each other in Q⟦t⟧: their product is 1, and both have constant term 1, so by [L9] (1−t)/(1+t)=1/PW(t) as a formal inverse. This is the identity verified in step 2.1 and shows that 1/PW is rational while PW has infinitely many positive coefficients.

4.1step 1.1step 2.1L4L5algebra∎

The rank-one parabolic W{s}={1,s} has PW{s}(t)=1+t=[2]t. The reduced forms in step 1.1 with no right t-descent are the identity and the alternating words ending in s, exactly one of each length; hence PW{t}=1+t+t2+⋯. By [L5], PW=PW{t}PW{t}=(1+t)(1+t+t2+⋯ ), which is not a polynomial. No finite m has [2]t[m]t=(1+t)/(1−t), since the left side is a polynomial and the right has infinitely many nonzero coefficients. The same group is denoted I2(∞).

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