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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

One color recovers two separated reaction columns of a sparse Jacobian

Example

Consider two independent first-order reactions A→k1B and C→k2D, with k1,k2>0 and state y=(a,b,c,d). Their vector field is F(y)=(−k1a,k1a,−k2c,k2c).

Facts & Assumptions

Given: The vector field and positive rates above.

[F1]

The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case: the Jacobian entries are the coordinate partial derivatives of the vector field.

[F2]

The column-interference graph and collision-free coloring for a sparse Jacobian: columns sharing a row support interfere; a color seed is the indicator vector of its columns.

[F3]

A collision-free column coloring recovers every structurally sparse Jacobian entry: a proper coloring of a safe support pattern recovers each Jacobian entry from the corresponding compressed product.

Verification

1.1givenF1F2algebra

Differentiating the four components in coordinate order (a,b,c,d), indexed 0,1,2,3, gives J=(−k1000k100000−k2000k20). The row supports are {0},{0},{2},{2}, so no row contains two columns and the coloring that assigns all four columns one color is proper.

2.1givenF2F3step 1.1algebra∎

Its seed is s=(1,1,1,1)T and Js=(−k1,k1,−k2,k2)T. Each row has at most one supported column of this color, so [F3] recovers the nonzero entries from these four values; the remaining entries are zero by the declared pattern.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources