Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-09-01
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Coordinate projections and inclusions on a finite product Banach space

Example

Let X and Y be Banach spaces over the same scalar field and equip X×Y with the maximum product norm

(x,y)max:=max{x,y}.

Then the coordinate projections

πX(x,y)=x,πY(x,y)=y,

and the coordinate inclusions

ιX(x)=(x,0),ιY(y)=(0,y)

are bounded linear operators. Moreover,

πX=ιX={1,X{0},0,X={0},πY=ιY={1,Y{0},0,Y={0}.

Facts & Assumptions

Given: Banach spaces X and Y over the same scalar field, their product X×Y with the maximum norm, and vectors xX, yY.

[L1]

The maximum product norm is one of the standard product norms (The standard product norms on a finite product of normed spaces).

[L2]

A finite product of Banach spaces is Banach, and bounded linear operators are the members of B(,) (Finite products of Banach spaces are Banach, A bounded linear operator between normed spaces, The spaces (\mathcal B(X,Y)) and (\mathcal B(X)) of bounded linear operators).

[L3]

The operator norm is the unit-ball supremum and therefore records the least global bound of a bounded linear operator (The operator norm as the least bound and as the unit-sphere or unit-ball supremum).

Verification

technique · direct
1.1

By [L1], (x,y)maxx and (x,y)maxy, so πX(x,y)(x,y)max and πY(x,y)(x,y)max. Thus both projections are bounded with operator norm at most 1 by [L2] and [L3].

L1L2L3
2.1

For xX and yY, [L1] gives ιX(x)max=(x,0)max=x and ιY(y)max=(0,y)max=y. So ιX1 and ιY1, with equality whenever the relevant domain is nonzero. If X{0}, choose uX with u=1. Then ιX(u)max=1, and also πX(u,0)=1=(u,0)max, so ιX=πX=1. If X={0}, then both ιX and πX are the zero operator, so both norms are 0. The same argument with Y gives the corresponding statements for ιY and πY.

step 1.1L1L3choose
3.1

Therefore πXB(X×Y,X), πYB(X×Y,Y), ιXB(X,X×Y), and ιYB(Y,X×Y), with the norms stated above.

step 1.1step 2.1L2

Depends on

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