Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The cosets of Q in R meet [0,1] in pairwise disjoint classes, and rational translates of a Vitali set count them

Example

Fix a Vitali set V⊆[0,1]. The equivalence classes of x∼y  ⟺  x−y∈Q meet [0,1] in pairwise disjoint pieces, and the rational translates of V count those classes exactly:

[0,1]⊆⋃q∈Q∩[−1,1](V+q)⊆[−1,2].

Facts & Assumptions

Given: A Vitali set V⊆[0,1].

[F1]

A Vitali set on [0,1] meets each class of x∼y  ⟺  x−y∈Q in exactly one point (Vitali set on [0,1]).

[L2]

Q is countably infinite (Q is countably infinite).

Verification

technique · direct
1.1F1

Two points x,y∈[0,1] lie in the same class exactly when they differ by a rational, and [F1] says that V contributes one and only one representative to each such class. Thus the pieces (x+Q)∩[0,1] are pairwise disjoint and each is hit once by V.

2.1step 1.1L2algebra∎

If t∈[0,1], let v∈V be the unique representative of its class. Then t−v∈Q and, because 0≤t,v≤1, also −1≤t−v≤1; so t∈V+q for some q∈Q∩[−1,1]. Conversely every v+q with v∈V and q∈[−1,1] lies in [−1,2].

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

20 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources