Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The rationals are dense but have dimension zero

Example

Assume the Axiom of Countable Choice. The set D=Q[0,1] has dimHD=0, although it is dense in [0,1] and its closure has dimension one. Hausdorff dimension need not be preserved by taking closure.

Facts & Assumptions

Given: The objects, conventions, and hypotheses in the statement above.

[F1]

Under the standing Countable Choice hypothesis, at most countable sets have Hausdorff dimension zero. Hausdorff dimension is monotone and countably stable

[F2]

Under the standing Countable Choice hypothesis, a subset of R with positive Lebesgue outer measure has dimension one. Euclidean space and positive-volume sets have their Euclidean dimension

[F4]

The rationals are countably infinite. Q is countably infinite

Verification

1.1

As a subset of the countable rationals, D is at most countable; hence dimHD=0. The endpoints zero and one are included.

F1F4
2.1

Every relative neighbourhood in [0,1] contains a rational point of [0,1], by density (and the endpoints themselves at the ends). Thus D=[0,1], whose Lebesgue measure is one and whose dimension is consequently one.

F2F3step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources