Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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x32 has discriminant 108 and Galois group S3 over Q

Example

x32 has Galois group S3 over Q. Its discriminant is 108.

Facts & Assumptions

Given: Eisenstein's irreducibility criterion at 2 (Eisenstein criterion over the integers) and the explicit splitting-field generators in The full S3 correspondence for the splitting field of x32.

[L1]

A monic irreducible separable cubic over a field of characteristic not two has group S3 when its discriminant is not a square (A monic irreducible separable cubic in characteristic not two has Galois group A3 or S3 according to its discriminant).

Verification

technique · direct
1.1

Eisenstein at 2 proves that x32 is irreducible over Q.

given
1.2

Its depressed-cubic discriminant is 27(2)2=108, which is nonzero and negative, hence is not a square in Q.

algebra
2.1

By [L1], steps 1.1 and 1.2 give Galois group S3, agreeing with the explicit six automorphisms of the splitting-field lattice example.

step 1.1step 1.2L1given

Depends on

Used by

Dependency tree · two levels

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Sources