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The ten-field D4 correspondence for the splitting field of x42

Example

Let a be the positive real fourth root of 2, let i2=1, and put L=Q(a,i). Define

r(a)=ia,r(i)=i,s(a)=a,s(i)=i.

Then Gal(L/Q)=r,s:r4=s2=1, srs=r1D4, and the complete correspondence is

SubgroupFixed field
{1}Q(a,i)
r2Q(a2,i)
sQ(a)
rsQ(a(1+i))
r2sQ(ia)
r3sQ(a(1i))
rQ(i)
r2,sQ(a2)
r2,rsQ(ia2)
D4Q

Facts & Assumptions

Given: Eisenstein's irreducibility criterion (Eisenstein criterion over the integers) and the normality correspondence of Normal subgroups, conjugate fields, and quotient groups in the Galois correspondence.

[L1]

In the finite Galois correspondence, [K:KH]=H and [KH:F]=[G:H], and the subgroup and intermediate-field assignments are mutually inverse bijections (The fundamental theorem of finite Galois theory).

[L2]

For a finite extension L/E with G=Aut(L/E), being Galois, being the splitting field of a separable polynomial, G=[L:E], and LG=E are equivalent (Equivalent characterizations of a finite Galois extension).

Verification

technique · direct
1.1

Eisenstein makes x42 irreducible, so [Q(a):Q]=4. Since Q(a)R and iR, adjoining i doubles the degree. Thus 1,a,a2,a3,i,ia,ia2,ia3 is a basis of the degree-eight splitting field L.

givenalgebra
2.1

The displayed maps preserve a4=2 and i2=1, permute the roots a,ia,a,ia, and satisfy r4=s2=1 and srs=r1; their eight composites are distinct. Those four roots are distinct, so x42 is separable and step 1.1 makes L its splitting field; by [L2], L/Q is finite Galois with Gal(L/Q)=[L:Q]=8. The eight composites therefore exhaust the automorphism group and give D4.

step 1.1L2construct
3.1

Applying the generators to the eight basis coefficients verifies that every field in the table is fixed by its displayed subgroup. Their degrees over Q are respectively 8,4,4,4,4,4,2,2,2,1.

step 2.1algebra
4.1

Those degrees equal the subgroup indices required by [L1], so each containment in step 3.1 is equality and the table is complete. The four reflection subgroups are nonnormal and give the nonnormal quartic fields; the remaining subgroups are normal and give the normal strict fields or endpoints.

step 3.1L1

Depends on

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