Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Delete-d replicates and subsampling on four units

Example

Take four observed real units z=(1,2,4,7) and use Tm(u1,…,um)=m−1∑j=1muj as the statistic at every nonempty subsample size. For delete-two jackknife replicates, remove each two-unit subset in turn and average the six size-two complement means. For subsampling, draw a two-unit subset uniformly without replacement and compute its mean.

Facts & Assumptions

Given: The ordered tuple (1,2,4,7) and the sample-mean statistic Tm(u1,…,um)=m−1∑j=1muj for m=2,4.

[F1]

Delete-d jackknife replicates and their uniform average: the delete-d procedure evaluates the declared size-(n−d) statistic on every complement of a d-subset and returns the uniform average of the replicates; it defines no variance scaling.

[F2]

Uniform subsampling without replacement: the subsampling procedure selects a uniformly distributed subset of the declared size without replacement and applies the corresponding statistic.

[F3]

Partial sums, row sums and sample means defines X‾m=m−1∑j=1mXj for real random variables on one probability space. Evaluating this finite-sum identity at an outcome gives the tuple formula declared in Given.

Verification

1.1givenF1F3algebra

The six deleted pairs {1,2},{1,3},{1,4},{2,3},{2,4},{3,4} leave complement means 11/2,9/2,3,4,5/2,3/2, respectively.

2.1F1F3step 1.1algebra

Their uniform average is (11/2+9/2+3+4+5/2+3/2)/6=7/2, equal to the original sample mean; [F1] supplies no multiplier or variance interpretation for that average.

3.1F1F2F3step 1.1step 2.1algebra∎

The six two-unit subsets have means 3/2,5/2,4,3,9/2,11/2, each with probability 1/6 by [F2]. The complement of every two-subset again has size two, and taking the complement twice returns the original subset; hence complementation bijects the deleted pairs with the sampled pairs. Therefore the size-two subsampling law has the same six equally weighted values as the delete-two replicate law in this example. The jackknife output in step 2.1 is their average, a single number, and is not a variance estimate.

Depends on

Used by

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Dependency tree · two levels

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Sources