Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Circle overlap weights count each arc once

Example

For S1=R/(2πZ) take the angular charts with images (π,π) and (0,2π). The coefficient one in both charts defines a positive smooth density with total mass 2π, for any subordinate partition.

Facts & Assumptions

Given: Assume ACω. Manifolds are Hausdorff, second countable and smooth, with boundary allowed; n=0 is allowed unless excluded. Densities are pointwise Borel, 0=0, and λ0(R0)=1. Circle overlap translations and a disjoint semicircle calculation.

[F1]

Intrinsic density measure and its chart restriction: Every Borel set in a chart has its coefficient integral, independent of partition.

[F2]

Measurable integration extends smooth density integration: Nonnegative integration equals the sum of weighted chart integrals.

Verification

1.1

Write q:RS1 for the quotient. The chart domains are U1=S1{q(π)} and U2=S1{q(0)}. On one overlap component x2=x1, and on the other x2=x1+2π. Both derivatives equal one, so the two constant coefficients satisfy the density law.

given
2.1

The disjoint decomposition is S1=q((0,π))q((π,2π)){q(0),q(π)}. The chart formula assigns the two arcs masses π and π, and the endpoints mass zero. Hence μr(S1)=2π.

F1F3step 1.1
3.1

For any subordinate pair (φ1,φ2), translate the negative-angle part of the first chart by 2π. Translation has unit Jacobian. The chart-sum formula becomes 02π(φ1(q(t))+φ2(q(t)))dt=02π1dt=2π, ignoring only the already null endpoints. Thus overlapping chart weights count each arc once. Empty arcs contribute zero.

F1F2F3step 1.1step 2.1

Depends on

Used by

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Dependency tree · two levels

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Sources