Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-09-01
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Differentiation on polynomials is unbounded for the supremum norm

Example

Let P[0,1] be the real polynomial functions on [0,1] with the supremum norm, and let

D:P[0,1]P[0,1],Dp:=p.

Then D is linear but not bounded for the supremum norm.

Facts & Assumptions

Given: The differentiation operator D on P[0,1] and the polynomials pn(x):=xn.

[L1]

A bounded linear operator requires one constant C such that DpCp for every polynomial p (A bounded linear operator between normed spaces).

Verification

technique · direct
1.1

Differentiation is linear on polynomials. For each n1, pn=1 on [0,1], while Dpn(x)=nxn1 and therefore Dpn=n.

givenalgebra
2.1

If D were bounded, [L1] would give a constant C with n=DpnCpn=C for every n1, impossible. Hence D is unbounded.

step 1.1L1assume-contradischarge-contradiction

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources