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ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A one-nearest-neighbor graph can disconnect finite ISOMAP

Example

Let x1=0, x2=1/10, x3=10, and x4=101/10 in R, use k=1, and symmetrize by union. The resulting undirected neighbor graph has exactly the two edges {1,2} and {3,4}, so it is disconnected. ISOMAP therefore returns its disconnected status and does not form finite all-pairs graph distances.

The diagram shows the two union-graph components; labels are the sample indices.

diagram failed to render:
\begin{tikzpicture}[vertex/.style={draw,circle,minimum size=7mm}]
  \node[vertex] (x1) at (0,0) {$1$};
  \node[vertex] (x2) at (1.4,0) {$2$};
  \node[vertex] (x3) at (4,0) {$3$};
  \node[vertex] (x4) at (5.4,0) {$4$};
  \draw (x1)--node[above] {$1/10$}(x2);
  \draw (x3)--node[above] {$1/10$}(x4);
\end{tikzpicture}

Facts & Assumptions

Given: The four stated real points, k=1, union symmetrization, and the ISOMAP connected-graph condition.

[F1]

The nearest-neighbor order is by (∥xi−xj∥2,j), and union edges are included when either endpoint selects the other (Deterministic finite nearest-neighbor lists and graph symmetrizations).

[F2]

ISOMAP returns a disconnected status and does not claim finite all-pairs graph distances when its graph is disconnected (Finite ISOMAP with deterministic neighborhoods and connected-graph shortest paths).

Verification

1.1givenF1algebra

The nearest neighbor of x1 and x2 is each other at distance 1/10; the nearest neighbor of x3 and x4 is each other at distance 1/10. Every distance between the two pairs is at least 99/10, so no cross-pair edge is selected. By [F1], the union graph has exactly the two edges {1,2} and {3,4}.

2.1step 1.1F2∎

The graph in step 1.1 has two connected components, so [F2] returns the disconnected status; a path between either cross-component pair does not exist, and the algorithm does not produce a finite all-pairs graph-distance matrix.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources