Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passaudited 2026-09-01
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Equivalent adic filtrations have canonically isomorphic completions

Example

Let R be a commutative ring, let M be an R-module, and let I,JR be ideals. Assume that there exist integers c,d>0 with IcJandJdI. Then the I-adic and J-adic topologies on M have the same completion: M^IM^J.

Facts & Assumptions

Given: A commutative ring R, an R-module M, ideals I,JR, and integers c,d>0 with IcJ and JdI.

[L1]

The I-adic and J-adic completions are the inverse limits of the quotient towers (M/InM) and (M/JmM) (The I-adic completion of a module).

[L2]

A compatible family of quotient maps induces a unique map into the corresponding inverse limit (Universal property of an inverse limit of modules).

Verification

technique · direct
1.1

For each k1, the inclusion IcJ gives IckMJkM and hence a quotient map M/IckMM/JkM. The powers ck form a cofinal subsystem of the I-adic tower. The displayed maps are compatible, so [L2] induces an R-linear map Φ:M^IM^J.

L1L2givenconstruct
1.2

Similarly, JdI gives compatible quotient maps M/JdkMM/IkM on a cofinal subsystem and hence a map Ψ:M^JM^I.

L1L2givenconstruct
2.1

On either side, composing the two systems of quotient maps eventually reduces modulo a larger and larger power of the same ideal. Hence the composites ΨΦ and ΦΨ induce the identity on every finite stage, so they are the identity on the inverse limits. Therefore Φ and Ψ are inverse isomorphisms.

step 1.1step 1.2algebra
3.1

Thus equivalent adic filtrations have canonically isomorphic completions.

step 2.1

Depends on

Used by

Dependency tree · two levels

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Sources