How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Equivalent adic filtrations have canonically isomorphic completions
Example
Let be a commutative ring, let be an -module, and let be ideals. Assume that there exist integers with Then the -adic and -adic topologies on have the same completion:
Facts & Assumptions
Given: A commutative ring , an -module , ideals , and integers with and .
The -adic and -adic completions are the inverse limits of the quotient towers and (The -adic completion of a module).
A compatible family of quotient maps induces a unique map into the corresponding inverse limit (Universal property of an inverse limit of modules).
Verification
For each , the inclusion gives and hence a quotient map The powers form a cofinal subsystem of the -adic tower. The displayed maps are compatible, so [L2] induces an -linear map
Similarly, gives compatible quotient maps on a cofinal subsystem and hence a map
On either side, composing the two systems of quotient maps eventually reduces modulo a larger and larger power of the same ideal. Hence the composites and induce the identity on every finite stage, so they are the identity on the inverse limits. Therefore and are inverse isomorphisms.
Thus equivalent adic filtrations have canonically isomorphic completions.
Depends on
Used by
Dependency tree · two levels
5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. S. Milne, A Primer of Commutative Algebra, Lemma 24.2 (standard reference, not scraped)
- The Stacks Project, Lemma 10.96.9 (standard reference, not scraped)